Heat Flow
MME 528
1. Physical Basics
heat flow
is due to three effects:
What is temperature?
see
Java applet at: http://mc2.cchem.berkeley.edu/Java/molecules/
a
measure of the average kinetic energy
of the molecules ( mc2/2)
so proportional to the mass of molecules and the square of
the
average speed
3 temperature
scales: Celsius, Fahrenheit, Kelvin (absolute)
What is heat?
the
transfer of energy from one object to another?
Experimental Fact #1
the
heat energy Q of a body is proportional to its mass and to its absolute
temperature T
Q = cmT
where c = specific
heat
Experimental Fact #2
the rate of flow of heat energy through a unit area of surface is
proportional to the temperature
difference on either side of the surface. The heat flows in the direction of decreasing
temperature
from hot to cold.
the
constant of proportionality k is called the thermal conductivity and depends on
the thickness of
the wall and the material
the
units of k are, in metric, calories per degree Kelvin per cm2
This is sometimes
referred to as Newton's Law of Cooling
2. Mathematical relationships
putting
these together one has, after Δt units of time
have elapsed,
(Q(t
+ Δt) – Q(t) )
= - kA(
T – Ts) Δt
in the
limit as Δt
-> 0 we get a derivative
dQ/dt = -kA( T – Ts)
but Q = cmT so dQ/dt = cm dT/dt so
cm dT/dt=
-kA(T – Ts)
or
dT/dt = - (kA/cm) (T- Ts)
where
T
= temperature in degrees Kelvin
t
= time
k
= constant of thermal conductivity
A
= cross sectional area
m
= mass
c
= specific heat of the material
Ts
= temperature of surroundings (fixed)
3. practical
implementation
the model
is linear
work in degrees Fahrenheit, ft, hours, BTUs
compute
heat flow per unit area
result: dQ/dt = - U A( T – Ts) is
the heat flow through a wall (note
changes)
where
U depends on physical material and its thickness (replacing k)
and is also per unit cross sectional area
and
A is the cross sectional area of the object.
further,
the inverse of U is called R and depends
on the material only, including its thickness
that
is, U = 1/R
Some sample U values:
door
glass: .650
roof
insulation (R – 19) .049
wall
insulation (R – 11, wooden studs) .088
3 1/2" standard walls
wooden
door (solid) .330
reference: http://www.ci.kent.wa.us/PermitCenter/BuildingServices/HeatLossCalc.pdf
4. Sample House:
single story ranch
2
wooden doors
120 ft2
of windows - single
pane
8' walls - 4" thick,
insulated, wood studs
45
degree roof - insulated with 6" of insulation
40'
x 24' overall
size
outside temp: 20 degrees F
inside : 70 degrees
heat
losses:
roof:
walls:
doors:
windows:
total: (this is BTUs per hour). Note:
1 gallon of heating oil has 139,000 BTU in it
question:
how many gallons of heating oil per day does this translate into??
Homework:
semester
schedule needed – last class is April 20th (14 meetings needed)
1. for a wall which is 8' high and
20' long, with conventional studs (16" on center), what
% of area is insulation,
what % is wood?
2. spreadsheet
total
heat flow for a rectangular house given
wall height, length, width, window area, # doors, roof pitch
columns
for outside temperature: 30,20,10,0 degrees F
standard
house
pie
chart showing, for one temp, the comparative heat loss due to
walls, windows, doors, roof
when
done, compute the daily oil consumption
3. more
R and U values
different
windows
floors
4. heat
loss of a house
shut
off heat, wait one hour
5.
what is a calorie??
how is it related to a BTU? what
is a watt??
6.
relationships of Celsius, Fahrenheit and Kelvin scales
7.
compare heat capacity and conductivity for the
following:
wood
(pine)
aluminum
Styrofoam
fiberglass
insulation
concrete
brick
rock (your choice)
water
air
8. volunteers needed to
demo TI CBL temperature probe in 2 weeks (1/20)
Florence and Mark have
volunteered…